Eric 的小站

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输入: s = "anagram", t = "nagaram"
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输出: true

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输入: s = "rat", t = "car"
2
输出: false

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class Solution {
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public:
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    bool isAnagram(string s, string t) {
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        if (s.size() != t.size())
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            return false;
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        int scount[26] = {0};
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        int tcount[26] = {0};
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        for (int i = 0; i < s.size(); i++) {
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            scount[s[i] - 'a']++;
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        }
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        for (int i = 0; i < t.size(); i++) {
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            tcount[t[i] - 'a']++;
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        }
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        for (int i = 0; i < 26; i++) {
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            if (scount[i] != tcount[i])
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                return false;
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        }
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        return true;
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    }
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};